114: Write a program that takes two integers as input and determines if the first number is positive, negative, or zero. If it's positive, check if it's even or odd. If it's negative, check if it's divisible by 3. Display appropriate messages for each case. Make this program using user defined functions


// Write a program that takes two integers as inputand determines if the first number is positive,negative, or zero.
// If it's positive, check if it's even orodd. If it's negative, check if it's divisible by 3.
// Display appropriate messages for each case.

#include <iostream>
using namespace std;
int inum(string x);
bool isPositive(int x);
bool isEven(int x);
bool isDivby3(int x);

int main()
{
    int num1 = inum("Enter first number: "), num2 = inum("Enter second number: ");
    if (isPositive(num1))
    {
        if (isEven(num1))
        {
            cout << num1 << " is positive even number\n";
        }
        else
        {
            cout << num1 << " is positive odd number\n";
        }
    }
    else
    {
        if (isDivby3(num1))
        {
            cout << num1 << " is negative and is divisible by 3\n";
        }
        else
        {
            cout << num1 << " is negative and is not divisible by 3\n";
        }
    }
    if (isPositive(num2))
    {
        if (isEven(num2))
        {
            cout << num2 << " is positive even number\n";
        }
        else
        {
            cout << num2 << " is positive odd number\n";
        }
    }
    else
    {
        if (isDivby3(num2))
        {
            cout << num2 << " is negative and is divisible by 3\n";
        }
        else
        {
            cout << num2 << " is negative and is not divisible by 3\n";
        }
    }

    return 0;
}

int inum(string x)
{
    int y;
    cout << x;
    cin >> y;
    return y;
}
bool isPositive(int x)
{
    return (x >= 0);
}
bool isEven(int x)
{
    return (x % 2 == 0);
}
bool isDivby3(int x)
{
    return (x % 3 == 0);
}



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