123: Write a program that takes three numbers as input and determines if they form an arithmetic progression. If they do, check if the common difference is positive or negative. Display appropriate messages for each case. Make this program using user defined functions.


// Write a program that takes three numbers as inputand determines if they form an arithmetic progression.
// If they do, check if the common difference is positive or negative.
// Display appropriate messages for each case.

#include <iostream>
using namespace std;
int inum(string x);
bool isAr_Progression(int x, int y, int z);
int common_difference(int x, int y, int z);
bool isPositive(int x);

int main()
{
    int num1 = inum("Enter first number: "),
        num2 = inum("Enter second number: "),
        num3 = inum("Enter third number: ");

    if (isAr_Progression(num1, num2, num3))
    {
        if (isPositive(common_difference(num1, num2, num3)))
        {
            cout << num1 << ", " << num2 << ", and " << num3 << " are in Arithmetic Progression\n";
            cout << "There common difference is: " << common_difference(num1, num2, num3) << " which is positive" << endl;
        }
        else
        {
            cout << num1 << ", " << num2 << ", and " << num3 << " are in Arithmetic Progression\n";
            cout << "There common difference is: " << common_difference(num1, num2, num3) << " which is negative" << endl;
        }
    }
    else
    {
        cout << num1 << ", " << num2 << ", and " << num3 << " are not in Arithmetic progression\n";
    }

    return 0;
}

int inum(string x)
{
    int y;
    cout << y;
    cin >> y;
    return y;
}
bool isAr_Progression(int x, int y, int z)
{
    return ((x - y) == (y - z));
}
int common_difference(int x, int y, int z)
{
    return x - y;
}
bool isPositive(int x)
{
    return !(x < 0);
}


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